Solving Literal Equations
Given that x, y and z are real numbers not equal to zero, solve for z: 3x2 -(4 - y) + 3z = 0.
A
z= -(3x^2 + y -4) / 3
B
z= 3x^2 + y -4 / 3
C
none of these is correct
D
z= -(3x^2 - y + 4) / 3
E
z= -(3x^2 + y -4) / 6
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